Authors

  • Ixbol Sadiqova
    Jizzakh state pedagogy university

DOI:

https://doi.org/10.71337/inlibrary.uz.ijai.73932

Abstract

This article unclear   integrals solution two main to the method , that is in pieces integration ( partial integration ) and variable exchange to the methods dedicated . This methods , unclear integrals in calculation complicated functions simplification and to calculate facilitate for wide is applied .The article firstly breaks down of integration main principles and his/her unclear integrals in solution how application seeing We will go out . This The method usually involves integrals simpler to expressions separation through the solution to find help gives .

 

 

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INTERNATIONAL JOURNAL OF ARTIFICIAL INTELLIGENCE

ISSN: 2692-5206, Impact Factor: 12,23

American Academic publishers, volume 05, issue 03,2025

Journal:

https://www.academicpublishers.org/journals/index.php/ijai

page 828

METHODS FOR SOLVING DEFINITE INTEGRALS

Sadiqova Ixbol Iskanderovna

Jizzakh state pedagogy university ,

Mathematician teaching methodology department teacher

e-mail:

iqbolsodiqova440@gmail.com

Abstract:

This article unclear integrals solution two main to the method , that is in pieces

integration ( partial integration ) and variable exchange to the methods dedicated . This methods ,

unclear integrals in calculation complicated functions simplification and to calculate facilitate for

wide is applied .The article firstly breaks down of integration main principles and his/her unclear

integrals in solution how application seeing We will go out . This The method usually involves

integrals simpler to expressions separation through the solution to find help gives .

Key words :

Indefinite integral, piecewise integration , variable exchange , mathematics analysis ,

integrals solve , functions simplification , variable exchange
In our country, mathematics has been identified as one of the priority areas for the development

of science in 2020. Over the past period, a number of systematic works have been carried out

aimed at bringing mathematical science and education to a new qualitative stage.
Resolution of the President of the Republic of Uzbekistan dated May 7, 2020 No. PQ-4708 “On

measures to improve the quality of education and develop scientific research in the field of

mathematics”, dated July 9, 2020 “On state support for the further development of mathematical

education and sciences, as well as the V.I. In connection with the rapid development of modern

branches of mathematics, science and technology, the foundation of which was laid by our great

ancestors such as Muhammad Al-Khwarizmi, Ahmad Al-Farghani, Abu Rayhon Beruni, Mirzo

Ulugbek, and the resolutions of the State Duma No. PQ-4387 “On measures to radically improve

the activities of the Romanovsky Institute of Mathematics”, the in-depth teaching of integrals,

one of the main topics in higher education, is currently one of the important issues. This article

serves to address the above-mentioned resolutions and the issues set before us.
Taking the above into account, we will study several methods for finding definite integrals of the

following form.

If

the equality holds

for ,

the function is called the

initial function of a

continuous

function on the interval.

Given function elementary function to find integration The function is called of integration one

how many methods there is is , this in the article in pieces integration method and variables

replacement method about stopped Let's go .

1. Integration by parts method .

If u(x) and v(x) are differentiable functions if so , in

pieces integration for

Formula (1) is used. This method

is

used

to

find

integrals

of

the

form

,

,

,

,


background image

INTERNATIONAL JOURNAL OF ARTIFICIAL INTELLIGENCE

ISSN: 2692-5206, Impact Factor: 12,23

American Academic publishers, volume 05, issue 03,2025

Journal:

https://www.academicpublishers.org/journals/index.php/ijai

page 829

,

,

, .

This method in use under the given integral f(x)dx

expression he *dv in appearance

choice must be , as a result of (1) – right on the side voodoo expression in integration initial

integral to find relatively simple Let it be .
In general he and dv what to choose separately attention to give necessary.If given integral

under expression plural and trigonometric or indicative functions from the multiplication

consists of if , then she is function as polytheism to take to the goal appropriate will be .

If the integral is function logarithmic and reverse trigonometric of functions in the plural

consists of if , then she is function as from differentiation then soda to look​

coming function

if taken good result gives .
In pieces integration repetitive in use initially she is with how function what designated if we

are then he /she with this function designation necessary , otherwise integral to zero without

equal will be .

Example 1.

Find the integral.

Solution

:

u=3x+5

and

We

get

uv

=

cos5x

.

Then

du=3dx,

Substituting this expression into formula (1), we obtain the

following:

Example 2.

Find the integral.

Solution :

(*)

Harvest made (*) PCB right by

To find the integral, we again use the formula for

integration by parts:

xln3xdx =

u = ln3x dv = xdx

du =

1

x

dx

v =

x

2

2

=

x

2

2 ln3x −

x

2

2 ln3xdx ==

x

2

2 ln3x −

x

2

4 + C

This is related to (*) given , given function integral


background image

INTERNATIONAL JOURNAL OF ARTIFICIAL INTELLIGENCE

ISSN: 2692-5206, Impact Factor: 12,23

American Academic publishers, volume 05, issue 03,2025

Journal:

https://www.academicpublishers.org/journals/index.php/ijai

page 830

w

e determine that.

2. Substitution of variables method .

Hypothesis let's do it Let the substitution be performed

in the integral

. If

a continuous function with an inverse has a

derivative

, then

(2)

The formula is valid. will be . (2) to unclear in the integral variable replacement formula It is

called .

Some in cases

Getting a replacement will yield good results.

The variable replacement given internal simple to look if it brings it , application to the

goal appropriate will be .

Uncertain in the integral variable replacement as a result found elementary in function

new variable instead of initial variable through expression leaving given of the integral answer

is defined . The function differential inside input , variable replacement method private is the

case .

Example 3.

Find the integral.

Solution

:

by

equality

variable

we

replace

,

then

and

Example 4.

Find the integral .

Solution :

We substitute the variable through the equation, then

dt = 4cos4xdx <=> cos4xdx =

1
4 dt

sin4x + 3cos4xdx =

1
4

t

1

2

dt =

1
4

t

3

2

3

2

+ C =

1
6

t

3

+ C

t=sin4x+3

=

1
6

sin4x + 3

3

+ C

Done replacement

differential of a function under to enter equivalent .


background image

INTERNATIONAL JOURNAL OF ARTIFICIAL INTELLIGENCE

ISSN: 2692-5206, Impact Factor: 12,23

American Academic publishers, volume 05, issue 03,2025

Journal:

https://www.academicpublishers.org/journals/index.php/ijai

page 831

REFERENCES:

1. T. Azlarov . H. Mansurov . Mathematician analysis . T. "Teacher", part 1. 1986.

2. Yes . S.​

Berman , Sbornik zadach po kursu matematicheskogo analiza.- M. , "Nauka"

1971 g.

3. N. S. Piskunov " Differential and integral calculus” 1-t. Chapters X, XI, XII.-T., “Teacher”,

1974.

4. I.I.Sadikova. Talabalarga aniqmas integrallarni hisoblash usullarini

o’rgatish.

https://wosjournals.com/index.php/medical/article/view/769

5. I.I.Sadikova. The problem of determining functions by spherical average

value.https://www.ijmrd.in/index.php/imjrd

References

T. Azlarov . H. Mansurov . Mathematician analysis . T. "Teacher", part 1. 1986.

Yes . S.​ Berman , Sbornik zadach po kursu matematicheskogo analiza.- M. , "Nauka" 1971 g.

N. S. Piskunov " Differential and integral calculus” 1-t. Chapters X, XI, XII.-T., “Teacher”, 1974.

I.I.Sadikova. Talabalarga aniqmas integrallarni hisoblash usullarini o’rgatish. https://wosjournals.com/index.php/medical/article/view/769

I.I.Sadikova. The problem of determining functions by spherical average value.https://www.ijmrd.in/index.php/imjrd